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Q.

A smooth inclined plane of length l, having an inclination θ with horizontal is inside a lift which is moving down will retardation a. The time taken by a body to slide down the inclined plane from rest will be

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a

2L/(asin⁡θ)

b

2L/(gsin⁡θ)

c

2L/(g−a)sin⁡θ

d

2L/(g+a)sin⁡θ

answer is D.

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Detailed Solution

Using s=ut+12at2, we have L=012(g+a)sin⁡θt2∴t=2L(g+a)sin⁡θ1/2On inclined plane, g sin θ is replaced by (g + a) sin θ as the lift is moving down with retardation a (this is equivalent to moving up with acceleration a).
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