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Q.

A smooth ring P of mass m can slide on a fixed horizontal rod. A string tied to the ring passes over a fixed pulley and carries a block Q of mass (m/2) as shown in the figure. At an instant, the string between the ring and the pulley makes an angle 60° with the rod. The initial acceleration of the ring is

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a

2g3

b

2g6

c

2g9

d

g3

answer is C.

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Detailed Solution

m2g−T=m2a  (I) Tcos⁡60∘=macos⁡60∘  (II) Solving ,acceleration of the ring , ar=2g9
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