A smooth ring P of mass m can slide on a fixed horizontal rod. A string tied to the ring passes over a fixed pulley and carries a block Q of mass (m/2) as shown in the figure. At an instant, the string between the ring and the pulley makes an angle 60° with the rod. The initial acceleration of the ring is
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a
2g3
b
2g6
c
2g9
d
g3
answer is C.
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Detailed Solution
m2g−T=m2a (I) Tcos60∘=macos60∘ (II) Solving ,acceleration of the ring , ar=2g9