A smooth sphere is moving on horizontal surface with a velocity vector (4i→+4j→) m/s immediately before it hit a vertically wall. The wall is parallel to vector j→ and coefficient of restitution between the sphere and the wall is e=12 . The velocity of the sphere after it hits the wall is
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a
i→−j→
b
-2i^+4j^
c
2i^+4j^
d
2i→−j→
answer is B.
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Detailed Solution
Wall is parallel to y-axis. Only x- component of velocity reverses. v→=-e4i^+4j^=12-4i^+4j^=-2i^+4j^