A smooth sphere is moving on a horizontal surface with velocity vector 2i^+2j^ immediately before it hits a vertical wall. The wall is parallel to j^ vector and the coefficient of restitution e=12 between the sphere and the wall is . The velocity vector of the sphere after it hits the wall is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
i^−j^
b
−i^+2j^
c
−i^−j^
d
2i^−j^
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
If y axis parallel to the wall. Velocity along y direction will not change.e = −VxUx = 12vx = −ux2 = −22 = −1Final velocity =−i+2j