A smooth sphere is moving on a horizontal surface with velocity vector 2i^+2j^ immediately before it hits a vertical wall. The wall is parallel to j^ vector and the coefficient of restitution between the sphere and the wall is e = 1/2. The velocity vector of the sphere after it hits the wall is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
i^−j^
b
−i^+2j^
c
−i^−j^
d
2i^−j^
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
j^ component, i.e., component of velocity parallel to wall remains unchanged while i^ component will become (-1/2)(2i^) or −i^ . Therefore, velocity vector of the sphere after it hits the wall is −i^+2j^