A smooth sphere is moving on a horizontal surface with velocity vector $$2i^+2j^$$ immediately before it hits a vertical wall. The wall is parallel to $$j^$$ vector and the coefficient of restitution between the sphere and the wall is e $$=$$ $$1/2$$. The velocity vector of the sphere after it hits the wall is

Question

A smooth sphere is moving on a horizontal surface with velocity vector $$2i^+2j^$$  immediately before it hits a vertical wall. The wall is parallel to $$j^$$ vector and the coefficient of restitution between the sphere and the wall is e $$=$$ $$1/2$$. The velocity vector of the sphere after it hits the wall is

Infinity Learn · Accepted Answer

$$j^$$ component, i.e., component of velocity parallel to wall remains unchanged while $$i^$$ component will become $$(-1/2)(2i^)$$  or  −$$i^$$ . Therefore, velocity vector of the sphere after it hits the wall is −$$i^+2j^$$

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A smooth sphere is moving on a horizontal surface with velocity vector 2i^+2j^ immediately before it hits a vertical wall. The wall is parallel to j^ vector and the coefficient of restitution between the sphere and the wall is e = 1/2. The velocity vector of the sphere after it hits the wall is

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