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A solenoid has a core of material with relative permeability 400. The windings of solenoid are insulated from the core and carry a current of 2 A. If no. of turns per unit length is 1000, the magnetising current

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Detailed Solution

If i is current in solenoid and im is magnetization currentB=μni=μ0ni+im ; μ0μrni=μ0ni+im im=μr-1i=400-1 x 2=399 x 2=798 A

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