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A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current of 5 A is passed through this solenoid, what is the magnetic field inside the solenoid?
 

a
6.28×10−4T
b
6.28×10−3T
c
6.28×10−7T
d
6.28×10−6T

detailed solution

Correct option is B

The magnetic field inside the solenoid is given by B =μ0ni0(n = number of turns per unit length, i = current in coil μ0=4⋅π×10−7Tm⁡/Awhere, n=NLr⇒n=4000.4×10−2×1×10−2⇒n=1000B=4×3.14×1000×5×10−7=63800×10−7=6.28×10−3T

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A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length. A current of 5 A pass through it. The magnetic field at the axis inside the solenoid is :


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