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Q.

A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length. A current of 5 A pass through it. The magnetic field at the axis inside the solenoid is :

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a

2π×10-3T

b

2π×10-5T

c

4π×10-2T

d

4π×10-3T

answer is A.

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Detailed Solution

n=10×102  turns/mB=μoni=4π×10−7×103×5=2π×10−3T
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