Questions
A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length. A current of 5 A pass through it. The magnetic field at the axis inside the solenoid is :
detailed solution
Correct option is A
n=10×102 turns/mB=μoni=4π×10−7×103×5=2π×10−3TTalk to our academic expert!
Similar Questions
A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current of 5 A is passed through this solenoid, what is the magnetic field inside the solenoid?
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