First slide

Solenoid

Question

A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length. A current of 5 A pass through it. The magnetic field at the axis inside the solenoid is :

Easy

A

$2 π \times 10^{- 3} T$
B

$2 π \times 10^{- 5} T$
C

$4 π \times 10^{- 2} T$
D

$4 π \times 10^{- 3} T$

Solution

$\begin{array}{l} n = 10 \times 10^{2} t u r n s / m \\ B = μ_{o} n i \\ = 4 π \times 10^{- 7} \times 10^{3} \times 5 \\ = 2 π \times 10^{- 3} T \end{array}$

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