Q.

A solenoid of 1 . 5 metre length and 4 .0 cm diameter possesses 10 turns per cm. A current of 5 ampere is flowing through it. The magnetic field at axis inside the solenoid is (Given:μ0=4π×10−7 weber/amp metre)

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2π×10−3 tesla

2π×10−5 tesla

4π×10−3 gauss

2π×10−5 gauss

answer is 1.

(Detailed Solution Below)

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Detailed Solution

B=μ0ni where n = number of turns per unit length μ0=4π×10−7TA−1m n=10cm−1=1000m−1,i=5amp∴ B=4π×10−7(1000)(5)=2π×10−3T

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