First slide
Solenoid
Question

A solenoid of 1 . 5 metre length and 4 .0 cm diameter possesses 10 turns per cm. A current of 5 ampere is flowing through it. The magnetic field at axis inside the solenoid is (Given:μ0=4π×107 weber/amp metre)

Easy
Solution

B=μ0ni where n = number of turns per unit length
 μ0=4π×107TA1m n=10cm1=1000m1,i=5amp B=4π×107(1000)(5)=2π×103T

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