A solid cube is placed on a horizontal surface. The coefficient of friction between them is μ, where μ<12.A . A variable horizontal force is applied on the cube’s upper ace, perpendicular to one edge and passing through the mid-point of that edge. The maximum acceleration with which it can move without toppling is
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a
μg
b
2μg
c
g2(1−2μ)
d
μ+12
answer is C.
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Detailed Solution
To avoid t topplingτnet 0=0F×a−mg×a2=0F=mg2Now apply Newton's laws of motion.