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A solid cylinder of mass 20 kg and radius 20 cm rotates about its axis with a angular speed 100 rad $s^{- 1}$ . The angular momentum of the cylinder about its axis is

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40 J s

400 J s

20 J s

200 J s

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detailed solution

Correct option is A

Here, M = 20 kg R = 20 cm = 20 × 10-2 m, ω = 100 rad s-1Moment of inertia of the solid cylinder about its axis isI = MR22 = (20 kg)(20×10-2 m)22 = 0.4 kg m2Angular momentum of the cylinder about axis isL = Iω = (0.4 kg m2)(100 rad s-1) = 40 J s

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A solid cylinder of mass 20 kg and radius 20 cm rotates about its axis with a angular speed 100 rad s-1. The angular momentum of the cylinder about its axis is

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A solid cylinder of mass 20 kg and radius 20 cm rotates about its axis with a angular speed 100 rad $s^{- 1}$ . The angular momentum of the cylinder about its axis is