Questions
A solid cylinder of mass 2 kg and radius 4 cm is rotating about its axis at the rate of 3 rpm. The torque required to stop after 2 revolutions is [NEET 2019]
detailed solution
Correct option is D
Given, mass of cylinder, m=2 kgRadius of cylinder, r=4 cm=4×10-2 mRotational velocity, 3rpm=3×2π60=π10rads-1 and θ=2π× revolution =2π×2π=4π2radThe work done in rotating an object by an angle θ from rest is given by W=τθAs the cylinder is brought to rest, so the work done will be negative.According to work-energy theorem,Work done = Change in rotational kinetic energy-τθ=12Iωf2-12Iωi2=12Iωf2-ωi2⇒ τ=Iωi22θ ∵ωf-0=1212mr2ωi2θ ∵I=12mr2( for cylinder )=14mr2ω2θ ∵ωi=ω=14×2×4×10-22×π102×14π2=14×2×16×10-4×π2100×14π2=2100×10-4=2×10-6 N-mTalk to our academic expert!
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