A solid cylinder of mass 2 kg and radius 4 cm rotating about its axis at the rate of 3 rpm. The torque required to stop after 2π revolution is
2×106 Nm
2×10-6 Nm
2×10-3Nm
12×10-4 Nm
ω0 = 3 rpm = 3×2π60rad/sec = π10 rad/sec
Using, ω2= ωo2+2αθ
02 = (π10)2+ 2(α)(2π×2π)
α =- 1800rad/sec2
Torque, τ = Iα= 12×2×0.042 (-1800) N-m = -2×10-6 N-m
Negative sign indicates that the applied torque is retarding in nature