Questions
A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 rev is
detailed solution
Correct option is D
Tr = IαApplying torque equation about center of cylinderτ = Iαα is the angular acceleration of cylinder and it is givenα = 2 revolution/s2 = 2×2π = 4π rad/s2T = Iαr = mr22×αr = mrα2 = 50×0.5×4π2N = 157 NTalk to our academic expert!
Similar Questions
Forces are applied on a wheel of radius 20 cm as shown in the figure. The torque produced by the forces 8 N at A, 8 N at E, 6 N at C and 9 N at D at angles indicated is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests