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Questions  

A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 rev s-2 is

a
25 N
b
50 N
c
78.5 N
d
157 N

detailed solution

Correct option is D

Tr = IαApplying torque equation about center of cylinderτ = Iαα is the angular acceleration of cylinder and it is givenα = 2 revolution/s2 = 2×2π = 4π rad/s2T = Iαr = mr22×αr = mrα2 = 50×0.5×4π2N = 157 N

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