First slide
Dynamics of rotational motion about fixed axis
Question

A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 revolutions  s-2is

Moderate
Solution

Here, mass of the cylinder, M = 50 kg 

Radius of the cylinder, R = 0.5 m

 Angular acceleration, α=2 rev s2=2×2πrads2=4πrads2

 Torque, τ=TR

Moment of inertia of the solid cylinder about its axis,

I=12MR2

  Angular acceleration of the cylinder 

α=τI=TR12MR2

T=MRα2=50×0.5×4π2=157N

 

 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App