First slide

Dynamics of rotational motion about fixed axis

Question

A solid cylinder of mass 3 kg rolling on a horizontal surface with velocity 4 m/s. It collides with a horizontal spring of force constant 200 N/m. The maximum compression produced in the spring will be :

Easy

A

0.7 m
B

0.2 m
C

0.5 m
D

0.6 m

Solution

From work energy theorem $\frac{1}{2} {Kx}^{2} = \frac{1}{2} {mv}^{2} (1 + \frac{K^{2}}{R^{2}})$
X = 0.6m

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