A solid cylinder of mass M and radius R rolls down an inclined plane of height h without slipping. The speed of its centre when it reaches the bottom is

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(2gh)

(43)gh

(34)gh

(4gh)

answer is B.

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Detailed Solution

12Iω2+ 12mv2 = mgh, ω = vr, I = 12mr2Solve to get v = (43)gh

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