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Q.

A solid cylinder of mass M and radius R rolls down an inclined plane of height h without slipping. The speed of its centre when it reaches the bottom is

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a

(2gh)

b

(43)gh

c

(34)gh

d

(4gh)

answer is B.

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Detailed Solution

12Iω2+ 12mv2 = mgh, ω = vr, I = 12mr2Solve to get v = (43)gh
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