A solid cylinder of mass M and radius R rolls down an inclined plane of height h without slipping. The speed of its centre when it reaches the bottom is
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a
(2gh)
b
(43)gh
c
(34)gh
d
(4gh)
answer is B.
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Detailed Solution
12Iω2+ 12mv2 = mgh, ω = vr, I = 12mr2Solve to get v = (43)gh