A solid cylinder of mass M and radius R without slipping down an inclined plane of length L and height h. What is the speed of centre of mass when the cylinder reaches bottom ?
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a
34gh
b
43gh
c
4gh
d
2gh
answer is B.
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Detailed Solution
Total K.E. of the cylinder at bottom is given by K.E. =12Iω2+12Mv2=12MR22v2R2+12Mv2=12Mv22+12Mv2=34Mv2Total K.E. at bottom = loss of potential energy∴ 34Mv2=Mgh or v=[(4/3)gh]