Q.

A solid cylinder rolls down an inclined plane of height 3 m and reaches the bottom of plane with angular velocity of 22rad·s-1. The radius of cylinder must be(Take g=10 ms-2)

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a

5cm

b

0.5cm

c

10 cm

d

5m

answer is D.

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Detailed Solution

v=2gh1+Imr2=2×10×31+mr22×mr2=2×10×332=40⇒v=rω⇒r=vω=4022=408=5m
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A solid cylinder rolls down an inclined plane of height 3 m and reaches the bottom of plane with angular velocity of 22rad·s-1. The radius of cylinder must be(Take g=10 ms-2)