Download the app

Questions  

The solid cylinder shown in figure is rolling without slipping between two moving planks P1 and P2 moving with velocities 2V and V respectively. If mass of the cylinder is m, then kinetic energy of the cylinder relative to ground frame is

a
18 mV2
b
1116 mV2
c
716 mV2
d
58 mV2

detailed solution

Correct option is B

Angular velocity of the cylinder ω=2V+V2R=3V2R∴   Velocity of centre C is given by V→C =  V→B +  V→C B∴  Kinetic energy relative to ground frame=12  mVC2  +  12 IC ω2  =  12 . m  V22  +  12  12  mR2.  3V2R2= 1116  mV2

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A sphere cannot roll without applying external force on 


phone icon
whats app icon