First slide
Rolling motion
Question

The solid cylinder shown in figure is rolling without slipping between two moving planks P1 and P2 moving with velocities 2V and V respectively. If mass of the cylinder is m, then kinetic energy of the cylinder relative to ground frame is

Difficult
Solution

Angular velocity of the cylinder ω=2V+V2R=3V2R

   Velocity of centre C is given by VC=  VB+  VCB

  Kinetic energy relative to ground frame

=12  mVC2  +  12ICω2  =  12.m  V22  +  12  12  mR2.  3V2R2

=1116  mV2

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