Q.

The solid cylinder shown in figure is rolling without slipping between two moving planks P1 and P2 moving with velocities 2V and V respectively. If mass of the cylinder is m, then kinetic energy of the cylinder relative to ground frame is

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a

18 mV2

b

1116 mV2

c

716 mV2

d

58 mV2

answer is B.

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Detailed Solution

Angular velocity of the cylinder ω=2V+V2R=3V2R∴   Velocity of centre C is given by V→C =  V→B +  V→C B∴  Kinetic energy relative to ground frame=12  mVC2  +  12 IC ω2  =  12 . m  V22  +  12  12  mR2.  3V2R2= 1116  mV2
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