A solid disc of mass 2 kg and radius 50 cm can rotate about an axis through its centre O and perpendicular to the plane of the disc. Forces are applied at points A, B and C as shown in figure. Then angular acceleration of the disc is

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2.5 rad/s2

5 rad/s2

10 rad/s2

20 rad/s2

answer is D.

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Detailed Solution

τ=Net torque about the centre =10sin30o×0.5+10×0.5−5×0.5N−m⇒τ=5 N−mI=12×2×0.52Kg−m2=0.25 Kg−m2∴ α=τI=50.25 rad/s2=20 rad/sec2

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