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A solid disc of mass 2 kg and radius 50 cm can rotate about an axis through its centre O and perpendicular to the plane of the disc. Forces are applied at points A, B and C as shown in figure. Then angular acceleration of the disc is
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Correct option is D
τ=Net torque about the centre =10sin30o×0.5+10×0.5−5×0.5N−m⇒τ=5 N−mI=12×2×0.52Kg−m2=0.25 Kg−m2∴ α=τI=50.25 rad/s2=20 rad/sec2Similar Questions
The instantaneous angular position of a point on a rotating wheel is given by the equation (t) = 2t3 6t2. The torque on the wheel becomes zero at [CBSE AIPMT 2011]
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