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Q.

A solid disc of mass 1 kg and radius 20 cm can rotate about an axis passing through its centre and perpendicular to its plane. A constant torque of 2 N-m is applied on the disc. Then its angular momentum after 5 sec is

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a

10 kg-m2/s

b

8 kg-m2/s

c

12 kg-m2/s

d

6 kg-m2/s

answer is A.

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Detailed Solution

I = Moment of inertia =12×1×0.22kg−m2=0.02kg−m2∴ Lf−Li=τ×t⇒Lf−0=2×5 kg−m2/s=10 kg−m2/s
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