Questions
A solid disc of mass 1 kg and radius 20 cm can rotate about an axis passing through its centre and perpendicular to its plane. A constant torque of 2 N-m is applied on the disc. Then its angular momentum after 5 sec is
detailed solution
Correct option is A
I = Moment of inertia =12×1×0.22kg−m2=0.02kg−m2∴ Lf−Li=τ×t⇒Lf−0=2×5 kg−m2/s=10 kg−m2/sTalk to our academic expert!
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The moment of inertia (I) and the angular momentum (L) are related by the expression [J&K CET 2013]
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