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A solid disc of mass 2 kg and radius 0.5 m is rotating about its own geometrical axis at 2 rps. A constant torque π N−m is applied on the disc. Then angular velocity of the disc after 10 sec will be

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a

18 π rad/s

b

24 π rad/s

c

44 π rad/s

d

34 π rad/s

answer is C.

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Detailed Solution

I=12×2×0.52=14 Kg−m2Angular acceleration, α=τI=π1/4rad/s2⇒α=4π rad/s2∴ ω=ω0+αt=2×2π+4π×10rad/s=44π rad/s
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