A solid disc of radius $$0.4$$ m can rotate about an axis passing through O its centre and perpendicular to the plane of the disc. Initially the disc is not rotating. Now a torque τ is applied on the disc which varies with time as shown in the figure. Then angular momentum of the disc at t $$=$$ $$3s$$ is

Question

A solid disc of radius $$0.4$$ m can rotate about an axis passing through O its centre and perpendicular to the plane of the disc. Initially the disc is not rotating. Now a torque τ is applied on the disc which varies with time as shown in the figure. Then angular momentum of the disc at t $$=$$ $$3s$$ is

Infinity Learn · Accepted Answer

Charge in angular momentum $$=$$ Angular impulse $$=$$ Area under τ−t graph. ∴ L−$$0=12$$×$$3$$×$$10$$ N−m−S⇒$$L=15$$ N−m−S

A solid disc of radius 0.4 m can rotate about an axis passing through O its centre and perpendicular to the plane of the disc. Initially the disc is not rotating. Now a torque $τ$ is applied on the disc which varies with time as shown in the figure. Then angular momentum of the disc at t = 3s is

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A solid disc of radius 0.4 m can rotate about an axis passing through O its centre and perpendicular to the plane of the disc. Initially the disc is not rotating. Now a torque τ is applied on the disc which varies with time as shown in the figure. Then angular momentum of the disc at t = 3s is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A solid disc of radius 0.4 m can rotate about an axis passing through O its centre and perpendicular to the plane of the disc. Initially the disc is not rotating. Now a torque $τ$ is applied on the disc which varies with time as shown in the figure. Then angular momentum of the disc at t = 3s is