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Q.

A solid disc of radius 0.4 m can rotate about an axis passing through O its centre and perpendicular to the plane of the disc. Initially the disc is not rotating. Now a torque τ is applied on the disc which varies with time as shown in the figure. Then angular momentum of the disc at t = 3s is

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a

12 N−m−S

b

15 N−m−S

c

10 N−m−S

d

20 N−m−S

answer is B.

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Detailed Solution

Charge in angular momentum = Angular impulse = Area under τ−t graph. ∴ L−0=12×3×10 N−m−S⇒L=15 N−m−S
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