A solid disc of radius $$0.30$$ m is suspended from a wire. The time period of its angular oscillation is $$3.14$$ s, if the torque constant of the wire is $$1.2$$×$$10$$−$$3$$ $$Nm/rad$$. Then the mass of the disc is

Question

A solid disc of radius $$0.30$$ m is suspended from a wire. The time period of its  angular oscillation is $$3.14$$ s, if the torque constant of the wire is  $$1.2$$×$$10$$−$$3$$  $$Nm/rad$$.  Then the mass of the disc is

Infinity Learn · Accepted Answer

For torsional pendulam,  $$T=2$$$$π$$IcHence moment of inertia will be   $$I=T24$$$$π$$$$2cI=$$π$$24$$$$π$$$$2$$×$$1.2$$×$$10$$−$$3$$  $$I=1.2$$×$$10$$−$$34=0.3$$×$$10$$−$$3$$    kg  $$m2For$$ a disc moment of inertia is $$MR22Hence$$  $$MR22=0.3$$×$$10$$−$$3$$  $$M=0.6$$×$$10$$−$$30.3$$×$$0.3$$  $$M=6.67$$  ×$$10$$−$$3$$   kg $$M=6.67$$ gram

A solid disc of radius 0.30 m is suspended from a wire. The time period of its angular oscillation is 3.14 s, if the torque constant of the wire is $1.2 \times 10^{- 3} N m / r a d$ . Then the mass of the disc is

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A solid disc of radius 0.30 m is suspended from a wire. The time period of its angular oscillation is 3.14 s, if the torque constant of the wire is 1.2×10−3 Nm/rad. Then the mass of the disc is

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A solid disc of radius 0.30 m is suspended from a wire. The time period of its angular oscillation is 3.14 s, if the torque constant of the wire is $1.2 \times 10^{- 3} N m / r a d$ . Then the mass of the disc is