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Q.

A solid disc is rolling without slipping on a horizontal surface. Then what fraction of its total energy is produced due to the transnational motion of the disc ?

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a

34

b

23

c

13

d

45

answer is B.

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Detailed Solution

(2)Energy due to transnational motion, KT=12 mV2Energy due to rotational motion, KT=12IC. ω2=12 12 mR2 VR2 = 14mV2∴ KTK = KTKr+KT = 12mV214 mV2+12mV2=23

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A solid disc is rolling without slipping on a horizontal surface. Then what fraction of its total energy is produced due to the transnational motion of the disc ?