First slide
Rolling motion
Question

A solid disc is rolling without slipping on a plane surface. If its kinetic energy of translation is 2 Joule, total kinetic energy of the disc

Moderate
Solution

Kinetic energy of translation, Kt=12mω2R2

Total energy E=12Iω2+12mω2R2=1212mR2ω2+12mω2R2

=342R2=34×2Kt=32×2Joule=3Joule

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