A solid disc is rolling without slipping on a plane surface. If its kinetic energy of translation is 2 Joule, total kinetic energy of the disc
6 Joule
4.5 Joule
3 Joule
4 Joule
Kinetic energy of translation, Kt=12mω2R2
Total energy E=12Iω2+12mω2R2=1212mR2ω2+12mω2R2
=34mω2R2=34×2Kt=32×2 Joule=3 Joule