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Q.

A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m=0.4kg is at rest on this surface. An impulse of  1.0Ns is applied to the block at time  t=0 so that it starts moving along the x-axis with a velocity  vt=v0e−t/τ, where v0  is a constant and  τ=4s. The displacement of the block, in metres, at  t=τ  is Take  e−1=0.37.

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answer is 6.30.

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Detailed Solution

V=V0e−t/τ                    here  V0=Jm=2.5m/s ⇒dxdt=V0e−t/τ⇒∫0xdx=V0∫0τe−t/τdt           Since∫e−xdx=e−x−1⇒x=V0e-t/τ-1τ⇒x=2.5 −4 e−1−e0                  ​⇒x=2.5−4 0.37−1​⇒x=6.30
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