A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m=0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time t=0 so that it starts moving along the x-axis with a velocity vt=v0e−t/τ, where v0 is a constant and τ=4s. The displacement of the block, in metres, at t=τ is Take e−1=0.37.
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answer is 6.30.
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Detailed Solution
V=V0e−t/τ here V0=Jm=2.5m/s ⇒dxdt=V0e−t/τ⇒∫0xdx=V0∫0τe−t/τdt Since∫e−xdx=e−x−1⇒x=V0e-t/τ-1τ⇒x=2.5 −4 e−1−e0 ⇒x=2.5−4 0.37−1⇒x=6.30