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Questions  

A solid non rotating steel ball of mass 1 kg, moving with a velocity of 4 m/s strikes a stationary steel ball of mass 2 kg. Just after the impact the velocity of the 1 kg ball becomes 2 m/s. If the duration of impact is 0.1 sec, then average impulsive force on each ball is 

a
20 N
b
30 N
c
40 N
d
200 N

detailed solution

Correct option is A

Magnitude of impulse on 1 kg ball is I where I = (1 x 4 -1 x 2) kg-m/s = 2 kg-m/s∴Average impulsive force F=I∆t=20.1N=20 N

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