Questions
A solid non rotating steel ball of mass 1 kg, moving with a velocity of 4 m/s strikes a stationary steel ball of mass 2 kg. Just after the impact the velocity of the 1 kg ball becomes 2 m/s. If the duration of impact is 0.1 sec, then average impulsive force on each ball is
detailed solution
Correct option is A
Magnitude of impulse on 1 kg ball is I where I = (1 x 4 -1 x 2) kg-m/s = 2 kg-m/s∴Average impulsive force F=I∆t=20.1N=20 NTalk to our academic expert!
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If two balls, each of mass 0.06 kg, moving in opposite directions with speed 4 m/s, collide and rebound with the same speed, then the impulse imparted to each ball due to other is
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