Questions
A solid sphere of mass 10 kg is placed on a rough surface having coefficient of friction = 0.1. A constant force F = 7 N is applied along a line passing through the center of the sphere as shown in the figure. The value of frictional force on the sphere is
detailed solution
Correct option is B
Let f the be frictional force towards left for pure rolling.a=R×α where a=F−fm=7−f10----(1)α=τI=fRI=fR25mR2=5f2mR Hence, 7−f10=5fR20R from(1) ⇒f=2NLimiting friction = fL=μmg=0.11010=10NSince, fTalk to our academic expert!
Similar Questions
A homogeneous solid cylindrical roller of radius R and mass M is pulled on a cricket pitch by a horizontal force. Assuming rolling without slipping, angular acceleration of the cylinder is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests