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Questions  

A solid sphere of mass m and radius r is released from rest from the given position. If it rolls without sliding on the circular track of radius R, its speed when it reaches its lowest position will be

a
87g(R−r)
b
107g(R−r)
c
109g(R−r)
d
57g(R−r)

detailed solution

Correct option is B

When the sphere reaches its lowest position it loses gravitational potential energy by ∆U and gains a kinetic energy by ∆K, where ∆U = -mg(R - r) and ΔK=12mvc21+K2R2=12mv21+25=710mv2 According to conservation of energy, ΔU+ΔK=0 or  −mg(R−r)+710mv2=0 or  v=107g(R−r)

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