A solid sphere of mass M and radius r slips on a rough horizontal plane. At some instant it has translational velocity v0 and rotational velocity about the centre v0/2r . The translational velocity after the sphere starts pure rolling

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6v07 in forward direction

6v07 in backward direction

7v06in forward direction

7v06 in backward direction

answer is A.

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Detailed Solution

Angular momentum can be conserved about lowest point.mv0r+25mr2v02r=mv'r+25mr2v'r⇒10mv0r+2Mv0r10=7mv'r5⇒v'=6v07

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