A Solid sphere of radius R carries a charge Q + q distributed uniformly over its volume. A very small point like piece of it of mass m gets detached from the bottom of the sphere and falls down vertically under gravity . This piece carries charge q. if it acquires a speed v when it has fallen through a vertical height y (see I figure ) then : ( assume the remaining portion to be spherical )
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
v2=yqQ4π∈0RR+ym+g
b
v2=yqQ4π∈0R2ym+g
c
v2=2yqQ4π∈0RR+ym+g
d
v2=2yQqR4π∈0R+y3m+g
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Gain in kinetic energy = loss in potential energy⇒KE= ΔUgravitational + ΔUelectric⇒12mv2= mgy + kQqR- kQqR+y⇒12mv2= mgy + kQq1R-1R+y ,where K=14π∈0⇒v2= 2yg+Qq4π∈0RR+ym