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Q.

A solid sphere of radius R is charged uniformly. The distance from the centre where the potential is half of its value at the centre

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a

2R

b

R/2

c

R/3

d

4R/3

answer is D.

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Detailed Solution

potential at the centre of sphere is Vc= 3kq2rpotential at some distance x from centre Vx=kqxgiven Vx=12Vc substitute and solvekqx=1232kqrx=4r3
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