A solid sphere of radius R is charged uniformly through out the volume. At what distance from its surface is the electrostatic potential half of the potential at the centre.
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a
R
b
R/2
c
R/3
d
2R
answer is C.
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Detailed Solution
Potential at centre Vc=K⋅3Q2RV1=K⋅QrK⋅3Q4R=KQrr=4R3Distance from surface 4R3−R=R3