A solid sphere of radius R is charged uniformly through out the volume. At what distance from its surface is the electrostatic potential half of the potential at the centre.

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R/2

R/3

answer is C.

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Detailed Solution

Potential at centre Vc=K⋅3Q2RV1=K⋅QrK⋅3Q4R=KQrr=4R3Distance from surface 4R3−R=R3

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