First slide

Pontial due to

Question

A solid sphere of radius R is charged uniformly through out the volume. At what distance from its surface is the electrostatic potential is one third of the potential at the centre.

Moderate

A

R
B

R/2
C

R/3
D

2R

Solution

Potential at centre $V_{c} = K . \frac{3 Q}{2 R}$
$\begin{array}{l} V_{1} = K . \frac{Q}{r} \\ K . \frac{3 Q}{6 R} = \frac{K Q}{r} \\ r = 2 R \end{array}$
Distance from surface $2 R - R = R$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App