Questions
A solid sphere rests on a horizontal surface. A horizontal impulse is applied at height h from centre. The sphere starts rolling just after the application of impulse. The
ratio h/r will be
detailed solution
Correct option is B
Rolling is rotation about point of contact. Applying impulse momentum equation about P.J(R+h)=IPω .....(i) and J=mv ......(ii) As sphere rolls v=ωR, and I=25mR2+mR2=75mR2 After solving, we get hR=25Talk to our academic expert!
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