Q.

A solid sphere rests on a horizontal surface. A horizontal impulse is applied at height h from centre. The sphere starts rolling just after the application of impulse. The ratio h/R will be

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a

12

b

25

c

15

d

23

answer is B.

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Detailed Solution

Rolling is rotation about point of contact. Applying impulse momentum equation about P.JR + h = IPω and J = mvAs sphere roll v = ωR, and I=25mR2+mR2=75mR2After solving, we get hR=25
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