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A solid sphere rests on a horizontal surface. A horizontal impulse is applied at height h from centre. The sphere starts rolling just after the application of impulse. The ratio h/R will be
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a
12
b
25
c
15
d
23
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Correct option is B
Rolling is rotation about point of contact. Applying impulse momentum equation about P.JR + h = IPω and J = mvAs sphere roll v = ωR, and I=25mR2+mR2=75mR2After solving, we get hR=25Similar Questions
A sphere cannot roll without applying external force on
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