A solid sphere rolls down two different inclined planes of the same heights but different angles of inclination. In both cases

detailed solution

Correct option is B

Speed of the rolling body at the bottom of inclined plane isv = 2gh1+k2R2where h is height of the inclined plane, k and R be radius of gyration and radius of the body respectively.For solid sphere, k2R2 = 25v =  2gh1+25  = 107ghAs h is same in both the cases, therefore speed will be same in both cases.Time of descent,      t = 1sinθ2hg(1+k2R2)Where θ is angle of inclination?For solid sphere, k2R2 = 25t = 1sinθ14 h5 gAs h is same but θ is different in both the cases, hence time of descend will be different in both the cases.