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A solid sphere is rotating about a diameter at an angular velocity $ω$ If it cools so that its radius reduces to $\frac{1}{n}$ of its original value, its angular velocity becomes

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ωn

ωn2

nω

n2ω

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detailed solution

Correct option is D

We know that I1ω1=I2ω2For solid sphere, the moment of inertia about diameter is given byI=25mr2∴ 25mr12ω1=25mr22ω2 or r12ω=r1n2ω2ω2=n2ω

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A solid sphere is rotating about a diameter at an angular velocity ω If it cools so that its radius reduces to 1nof its original value, its angular velocity becomes

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A solid sphere is rotating about a diameter at an angular velocity $ω$ If it cools so that its radius reduces to $\frac{1}{n}$ of its original value, its angular velocity becomes