A solid sphere is sliding with a velocity V0 on a rough horizontal surface. Its velocity when it starts pure rolling is

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57v0

27v0

v014

5v014

answer is A.

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Detailed Solution

By conservation of angular momentum mv0r=Iω + mvrmv0r=25mr2ω + mvrv0=25rω + v=75v v=rωv=5v07

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