A solid sphere and a solid cylinder of same mass are rolled down on two inclined planes of heights h1 and h2, respectively. If at the bottom of the plane, the two objects have same linear velocities, then the ratio of h1 : h2 is

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2 : 3

7: 5

14 : 15

15: 14

answer is C.

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Detailed Solution

According to the question,KTsphere =KTcylinder (m and v are same)∴ 57mgh1=23mgh2⇒ h1h2=1415

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