Questions
A solid sphere of uniform density and radius R applies a gravitational force of attraction on a particle placed at a distance 2R from the centre of the sphere. A spherical cavity of radius (R/2) is now made in the sphere as shown in Figure. The sphere with cavity now applies a gravitational force on the same particle. The ratio is:
detailed solution
Correct option is D
F1=GMm2R2=x4---(1) ,whereGMmR2=x F'=GM'm32R2=GM/8m9/4R2=x18 (as M’ is the mass of the cavity) Thus F2=F1−F'=x4−x18=7x36---(2) from (1) and (2) we get or F2F1=7x36×4x=79Talk to our academic expert!
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The percentage change in the acceleration of the earth towards the Sun from a total eclipse of the Sun to the point where the Moon is on a side of earth directly opposite to the Sun is
(Take r1 as the distance between the sun and the earth, r2 as the distance between the earth and the moon, Ms , Me and Mm are the masses of the sun, the earth and the moon respectively)
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