A solid sphere of uniform density and radius R applies a gravitational force of attraction equal to $$F1$$ on a particle placed at a distance $$2R$$ from the centre of the sphere. A spherical cavity of radius (R/2) is now made in the sphere as shown in Figure. The sphere with the cavity now applies a gravitational force $$F2$$ on the same particle. The ratio (F2/F1) is :

Question

Infinity Learn · Accepted Answer

⇒$$F1=GMm(2R)2$$,$$F2=GMm(2R)2$$−$$GM8m3R22=7GMm36R2$$⇒$$F2F1=7/361/4=79$$

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