A solid uniform ball having volume V and density r floats at the interface of two immiscible liquids as shown in figure.The densities of the upper and the lower liquids are ρ1 and ρ2 respectively, such that ρ1<ρ<ρ2. What fraction of the volume of the ball will be in the lower liquid :
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a
ρ−ρ2ρ1−ρ2
b
ρ1ρ1−ρ2
c
ρ1−ρρ1−ρ2
d
ρ1−ρ2ρ2
answer is C.
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Detailed Solution
In floating conditionW = ThLet V1 volume immersed in lower liquid thenVρg=V−V1ρ1g+V1ρ2gVρ−ρ1=V1ρ2−ρ1V1V=ρ−ρ1ρ2−ρ1=ρ1−ρρ1−ρ2