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Questions  

Solve the following Integrals cos3θ1sinθdθ

a
sin⁡θ-sin2⁡θ2+C
b
sin⁡θ+cos2⁡θ2+C
c
cos⁡θ+cos2⁡θ2+C
d
sin⁡θ−cos2⁡θ2+C

detailed solution

Correct option is D

∫1−sin2⁡θ1−sin⁡θcos⁡θdθ  put sin⁡θ=t;cos⁡dθ=dt∫1−t21−tdt=∫(1+t)dt=t+t22+c=sin⁡θ+sin2⁡θ2+c

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