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Q.

Solve the following Integrals ∫cos3⁡θ1−sin⁡θdθ

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a

sin⁡θ-sin2⁡θ2+C

b

sin⁡θ+cos2⁡θ2+C

c

cos⁡θ+cos2⁡θ2+C

d

sin⁡θ−cos2⁡θ2+C

answer is D.

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Detailed Solution

∫1−sin2⁡θ1−sin⁡θcos⁡θdθ  put sin⁡θ=t;cos⁡dθ=dt∫1−t21−tdt=∫(1+t)dt=t+t22+c=sin⁡θ+sin2⁡θ2+c
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