Questions
A sonometer wire has a length of 114 cm between two fixed ends, where should two bridges be placed to divide the wire into three segments whole fundamental frequencies are in the ratio ?
detailed solution
Correct option is A
In case of a given wire under constant tension Fundamental frequency of vibration f ∝1l ∴l1:l2:l3=11:13:14=12:4:3 l1=1219×114⇒l1=72 cm l2=24 cm l3=18 cm ∴ First bridge is to be placed 72 cm from one end. Second bridge is to be placed 72+24=96 cm from one endTalk to our academic expert!
Similar Questions
A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)
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