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Stationary waves

Question

A sonometer wire of length 1.5m is made of steel. The tension in it produce an elastic strain of 1%. What is the fundamental frequency of transverse vibrations in Hz if density and young’s modulus of steel are  7.7×103 kg/m3 and 15.4×1011 N/m2 respectively? 2=1.414,3=1.732,5=2.236

Moderate
Solution

Given length of wire  l=1.5 m
Young’s modulus  Y=stressstrain=15.4×1011 N/m2
Stress=Tension/Cross section area
 = TA
Strain=1%=0.01
15.4×1011=T/A0.01

15.4×1011=T0.01A

T=15.4×109×A

Volume density  d=7.7×103 kg/m3
Linear density  μ=Volume density×Area
=d×A      
=7.7×103×A     
Velocity of transverse wave on the sonometer wire V=Tμ
V=15.4×1097.7×103 =2×103m/s 
Fundamental note has a wave length  λ=2L=3 m
So, frequency= Vλ=2×1033=471.33Hz.
 



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