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A sonometer wire resonates with a given tuning fork forming standing waves with five antinodes between the two bridges when a mass of 9 kg is suspended from the wire. When this mass is replaced by a mass M, the wire resonates with the same tuning fork forming three antinodes for the same positions of the bridges. The value of M is 

a
25 kg
b
5 kg
c
12.5 kg
d
1/25 kg

detailed solution

Correct option is A

The frequency of vibration of a string n=p2lTmAlso number of loops = Number of antinodes. Hence, with 5 antinodes and hanging mass of 9 kg.We have p = 5 and T = 9g ⇒n1=52l9gmWith 3 antinodes and hanging mass M We have p = 3 and T = Mg ⇒n2=32lMgm∵n1=n2⇒52l9gm=32lMgm⇒M=25kg

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A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)


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