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In a sonometer wire, the tension is maintained by suspending a 50.7 kg mass from the free end of the wire. The suspended mass has a volume of 0.0075 m3. The fundamental frequency of the wire is 260 Hz. If the suspended mass is completely submerged in water, the fundamental frequency will become (take g = 10 ms–2

a
240 Hz
b
230 Hz
c
220 Hz
d
200 Hz

detailed solution

Correct option is A

n=p2lTm∝T⇒n1n2=T1T2⇒260n2=50.7g(50.7−0.0075×103)g⇒n2≈240 Hz

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